Actual source code: baijsolvtrannat2.c
petsc-3.10.5 2019-03-28
1: #include <../src/mat/impls/baij/seq/baij.h>
3: PetscErrorCode MatSolveTranspose_SeqBAIJ_2_NaturalOrdering_inplace(Mat A,Vec bb,Vec xx)
4: {
5: Mat_SeqBAIJ *a=(Mat_SeqBAIJ*)A->data;
6: PetscErrorCode ierr;
7: PetscInt i,nz,idx,idt,oidx;
8: const PetscInt *diag = a->diag,*vi,n=a->mbs,*ai=a->i,*aj=a->j;
9: const MatScalar *aa =a->a,*v;
10: PetscScalar s1,s2,x1,x2,*x;
13: VecCopy(bb,xx);
14: VecGetArray(xx,&x);
16: /* forward solve the U^T */
17: idx = 0;
18: for (i=0; i<n; i++) {
20: v = aa + 4*diag[i];
21: /* multiply by the inverse of the block diagonal */
22: x1 = x[idx]; x2 = x[1+idx];
23: s1 = v[0]*x1 + v[1]*x2;
24: s2 = v[2]*x1 + v[3]*x2;
25: v += 4;
27: vi = aj + diag[i] + 1;
28: nz = ai[i+1] - diag[i] - 1;
29: while (nz--) {
30: oidx = 2*(*vi++);
31: x[oidx] -= v[0]*s1 + v[1]*s2;
32: x[oidx+1] -= v[2]*s1 + v[3]*s2;
33: v += 4;
34: }
35: x[idx] = s1;x[1+idx] = s2;
36: idx += 2;
37: }
38: /* backward solve the L^T */
39: for (i=n-1; i>=0; i--) {
40: v = aa + 4*diag[i] - 4;
41: vi = aj + diag[i] - 1;
42: nz = diag[i] - ai[i];
43: idt = 2*i;
44: s1 = x[idt]; s2 = x[1+idt];
45: while (nz--) {
46: idx = 2*(*vi--);
47: x[idx] -= v[0]*s1 + v[1]*s2;
48: x[idx+1] -= v[2]*s1 + v[3]*s2;
49: v -= 4;
50: }
51: }
52: VecRestoreArray(xx,&x);
53: PetscLogFlops(2.0*4.0*(a->nz) - 2.0*A->cmap->n);
54: return(0);
55: }
57: PetscErrorCode MatSolveTranspose_SeqBAIJ_2_NaturalOrdering(Mat A,Vec bb,Vec xx)
58: {
59: Mat_SeqBAIJ *a=(Mat_SeqBAIJ*)A->data;
60: PetscErrorCode ierr;
61: const PetscInt n=a->mbs,*vi,*ai=a->i,*aj=a->j,*diag=a->diag;
62: PetscInt nz,idx,idt,j,i,oidx;
63: const PetscInt bs =A->rmap->bs,bs2=a->bs2;
64: const MatScalar *aa=a->a,*v;
65: PetscScalar s1,s2,x1,x2,*x;
68: VecCopy(bb,xx);
69: VecGetArray(xx,&x);
71: /* forward solve the U^T */
72: idx = 0;
73: for (i=0; i<n; i++) {
74: v = aa + bs2*diag[i];
75: /* multiply by the inverse of the block diagonal */
76: x1 = x[idx]; x2 = x[1+idx];
77: s1 = v[0]*x1 + v[1]*x2;
78: s2 = v[2]*x1 + v[3]*x2;
79: v -= bs2;
81: vi = aj + diag[i] - 1;
82: nz = diag[i] - diag[i+1] - 1;
83: for (j=0; j>-nz; j--) {
84: oidx = bs*vi[j];
85: x[oidx] -= v[0]*s1 + v[1]*s2;
86: x[oidx+1] -= v[2]*s1 + v[3]*s2;
87: v -= bs2;
88: }
89: x[idx] = s1;x[1+idx] = s2;
90: idx += bs;
91: }
92: /* backward solve the L^T */
93: for (i=n-1; i>=0; i--) {
94: v = aa + bs2*ai[i];
95: vi = aj + ai[i];
96: nz = ai[i+1] - ai[i];
97: idt = bs*i;
98: s1 = x[idt]; s2 = x[1+idt];
99: for (j=0; j<nz; j++) {
100: idx = bs*vi[j];
101: x[idx] -= v[0]*s1 + v[1]*s2;
102: x[idx+1] -= v[2]*s1 + v[3]*s2;
103: v += bs2;
104: }
105: }
106: VecRestoreArray(xx,&x);
107: PetscLogFlops(2.0*bs2*(a->nz) - bs*A->cmap->n);
108: return(0);
109: }